Android Guides | Samples

Android.App.Dialog.OnCreatePanelView Method

Instantiate the view to display in the panel for 'featureId'.

Syntax

[Android.Runtime.Register("onCreatePanelView", "(I)Landroid/view/View;", "GetOnCreatePanelView_IHandler")]
public virtual View OnCreatePanelView (Int32 featureId)

See Also

Parameters

featureId
Which panel is being created.

Remarks

Instantiate the view to display in the panel for 'featureId'. You can return null, in which case the default content (typically a menu) will be created for you.

[Android Documentation]

Requirements

Namespace: Android.App
Assembly: Mono.Android (in Mono.Android.dll)
Assembly Versions: 0.0.0.0
Since: Added in API level 1